Skip to main content

simple program to create Orphan process

shiv@ubuntu:~/ds/unix$ cat  orp.c
/*
 * Program to create orphan process @ Linux
 * getpid() gives process PID and 
 * getppid() gives process's parent ID 
 * here main() process ID is parent id is current shells PID
 * once process becomes orphan it is adopted by init process(it's PID is 1)
 */
 
#include<stdio.h>
#include<unistd.h>
int main()
{

 pid_t p;

/* create child process */
 p=fork();

 if(p==0) {
    /* fork() returns Zero to child */
    sleep(10);
 }
 printf("The child process pid is %d parent pid %d\n", getpid(), getppid());
/*parent/child waits for 20 secs and exits*/
 sleep(20);
 printf("\nProcess %d is done its Parent pid %d...\n", getpid(), getppid());

 return 0;
}

O/p
shiv@ubuntu:~/ds/unix$ ./a.out
The child process pid is 2575 parent pid 1922
The child process pid is 2576 parent pid 2575

Process 2575 is done its Parent pid 1922...
shiv@ubuntu:~/ds/unix$
Process 2576 is done its Parent pid 1...




Comments

Post a Comment

Popular posts from this blog

C Program to Simulate Linux Cat command

/*  * C program to Simulate Implementation of  Linux *cat* command  * This program will not handle redirection  * you can try to improve this program to handle redirection of file contents  */ #include<stdio.h> #include<string.h> #define MAX_FILE_NAME_CHARS 255 int main(int argc, char *argv[]) {  FILE *fp;  char file_name[MAX_FILE_NAME_CHARS], ch;  int i;  /*   * after creating a.out, rename it as mycat for our own cat command   * and it usage is same as standard cat command   */  if(argc<1){     printf("Usage mycat <filename> \n");     return 0;  }  /*   * cat handles more than one file   * so we need this loop to handle all the files provided   * on command line   */  for(i=1; i<=argc;i++){     /* no need of copy but for understanding purpose, i have created      * str...

C Program to find Armstrong numbers between range m and n

/*  * Program to print Armstrong number between range m and n  * Armstrong  number is nothing but sum of cubes of digits of number is  * equal to the number  * ex: 153 is Armstrong number since 1^3+5^3+3^3=153  * there are very few numbers hold above property; execute   * below program to find all numbers  * b/w m and n  */ #include <stdio.h> void is_armstrong(int num) {   int sum=0, n, d;   n=num;   while(n){   d=n%10;  /* extract digits of number*/   sum=sum+(d*d*d);  /*take sum of them */   n=n/10;  }  if(sum == num)  /*sum is same as number then it is Armstrong number*/     printf("%d\n", sum); } int main() { int i,n,m; printf("Enter range \n"); scanf("%d%d", &m, &n);  for(i=m;i<=n;i++){    is_armstrong(i);  } return 0; }